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x^2-1.5x-1.44=0
a = 1; b = -1.5; c = -1.44;
Δ = b2-4ac
Δ = -1.52-4·1·(-1.44)
Δ = 8.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{8.01}}{2*1}=\frac{1.5-\sqrt{8.01}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{8.01}}{2*1}=\frac{1.5+\sqrt{8.01}}{2} $
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